A) The rate is proportional to the concentration of substrate.
B) The reaction is favored in polar protic solvents.
C) The rate is independent of the concentration of the nucleophile.
D) The electrophilic carbon undergoes inversion of stereochemistry.
Correct Answer
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Multiple Choice
A) SN1, CH3OH
B) SN1, DMSO
C) SN2, CH3OH
D) SN2, DMSO
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) Carbocations are stabilized by electron-withdrawing inductive effects only.
B) Carbocations are stabilized by electron-withdrawing inductive effects and hyperconjugation.
C) Carbocations are stabilized by electron-donating inductive effects only.
D) Carbocations are stabilized by electro-donating inductive effects and hyperconjugation.
Correct Answer
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Multiple Choice
A) Only I
B) Only II
C) I and II
D) None
Correct Answer
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Multiple Choice
A) Only I
B) Only II
C) I and II
D) None
Correct Answer
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Multiple Choice
A) SN1, CH3OH
B) SN1, HMPA
C) SN2, CH3OH
D) SN2, HMPA
Correct Answer
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Multiple Choice
A) F-
B) Cl-
C) Br-
D) I-
Correct Answer
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Multiple Choice
A) IV < II < III < I
B) III < IV < I < II
C) II < IV < I < III
D) I < III < II < IV
Correct Answer
verified
Multiple Choice
A) They don't undergo SN1 reactions because a higher percent s-character makes the bond longer and stronger.
B) They don't undergo SN2 reactions because a higher percent s-character makes the bond shorter and stronger.
C) They don't undergo SN2 reactions because heterolysis of the C-X bond forms a highly unstable carbocation.
D) They don't undergo SN1 reactions because the carbocation is highly electronegative.
Correct Answer
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Multiple Choice
A) Reaction of the nucleophile with the carbocation to form the product.
B) Breaking the bond between the carbon and the leaving group to generate a carbocation.
C) Attack of the nucleophile on the substrate to generate a pentavalent carbon.
D) None of these.
Correct Answer
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Multiple Choice
A) 2-Bromo-5,5-dimethylheptane
B) 3,3-Dimethyl-6-bromoheptane
C) 6-Bromo-3,3-dimethylheptane
D) 2-Bromo-5,5-dimethyloctane
Correct Answer
verified
Multiple Choice
A) I > II > III > IV
B) IV > I > II > III
C) IV > III > II > I
D) III > II > I > IV
Correct Answer
verified
Multiple Choice
A) All good leaving groups are weak bases with strong conjugate acids.
B) Left-to-right across a row of the periodic table, leaving group ability increases.
C) Down a column of the periodic table, leaving group ability increases.
D) Equilibrium favors the products of the nucleophilic substitution when the leaving group is a stronger base than the nucleophile.
Correct Answer
verified
Multiple Choice
A) Sodium ethoxide is a better nucleophile than sodium tert-butoxide.
B) Sodium tert-butoxide and sodium ethoxide have similar strengths as bases.
C) Sterically hindered bases are also called nonnucleophilic bases.
D) Steric hindrance decreases basicity but not nucleophilicity.
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) (R) -3-Bromo-1-methylcyclohexene
B) (S) -3-Bromo-1-methylcyclohexene
C) (S) -1-Bromo-3-methyl-2-cyclohexene
D) (R) -1-Bromo-3-methyl-2-cyclohexene
Correct Answer
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Multiple Choice
A) IV < III < II < I
B) I < IV < III < II
C) I < II < III < IV
D) II < I < III < IV
Correct Answer
verified
Multiple Choice
A) I > II > III
B) II > I > III
C) III > I > II
D) I > III > II
Correct Answer
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